- A$\text{CO}_2$is formed as the product.
- BReaction is exothermic.
- C$\text{MnO}_4^-$ catalyses the reaction.
- D$\text{Mn}^{2+}$acts as autocatalyst.
Explanation:
When KMnO4 solution is added to oxalic acid solution, the decolourisation is slow in the beginning but becomes instantaneous after some time because Mn2+ acts as an autocatalyst.
Reduction half $\text{MnO}^-_4+8\text{H}^++5\text{e}^-\rightarrow\text{Mn}^{2+}+4\text{H}_2\text{O]}\times2$
Oxidation half $\text{C}_2\text{O}_4^{2-}\rightarrow2\text{CO}_2+2\text{e}^-]\times5$
Overall equation $2\text{MnO}_4^-+16\text{H}^++5\text{C}_2\text{O}_4^{2-}\rightarrow2\text{Mn}^{2+}+10\text{CO}_2+8\text{H}_2\text{O}$
End point of this reaction Colourless to light pink
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$MnO_4^ - \, + \,x{e^ - }\,\xrightarrow[{(Alkaline\,\,medium)}]{}MnO_4^{2 - }$
$MnO_4^ - \, + \,y{e^ - }\,\xrightarrow{{(Acidic\,\,medium)}}M{n^{2 + }}$
$MnO_4^ - \, + \,z{e^ - }\,\xrightarrow{{(Neutral\,\,medium)}}Mn{O_2}$
In the given reaction sequence $B$ and $C$ are :
($R$ is gas constant)