MCQ
When lead storage battery is charged
- ALead dioxide dissolves
- ✓Sulphuric acid is regenerated
- CThe lead electrode becomes coated with lead sulphate
- DThe amount of sulphuric acid decreases
Cathode $-\mathrm{PbSO}_{4}+2 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{PbO}_{2}+4 \mathrm{H}^{+}+\mathrm{SO}_{4}^{2-}+2 \mathrm{e}^{-}$
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$CO + \frac{1}{2}{O_2} \to C{O_2};\,\Delta H = Y$
Then the heat of formation of $CO$ is