MCQ
When lead storage battery is charged
- ALead dioxide dissolves
- ✓Sulphuric acid is regenerated
- CThe lead electrode becomes coated with lead sulphate
- DThe amount of sulphuric acid decreases
Cathode $-\mathrm{PbSO}_{4}+2 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{PbO}_{2}+4 \mathrm{H}^{+}+\mathrm{SO}_{4}^{2-}+2 \mathrm{e}^{-}$
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$X + Y\mathop {\xrightarrow{{NaOH}}}\limits_{5\,^oC} \begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - CH - CH - CHO} \\
{\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
$(X)$ and $(Y)$ will respectively be :