MCQ
When primary amines are treated with $HCl$, the product obtained is
- AAn alcohol
- BA cyanide
- CAn amide
- ✓Ammonium salt
✓
Answer
Correct option: D.
Ammonium salt
d
(d) $C{H_3} - C{H_2} - N{H_2} + HCl \to \mathop {C{H_3}C{H_2} - NH_3^ + C{l^ - }}\limits_{{\rm{Ethyl}}\,\,{\rm{ammonium}}\,\,{\rm{chloride}}} $
(d) $C{H_3} - C{H_2} - N{H_2} + HCl \to \mathop {C{H_3}C{H_2} - NH_3^ + C{l^ - }}\limits_{{\rm{Ethyl}}\,\,{\rm{ammonium}}\,\,{\rm{chloride}}} $
Amines are basic in nature they react with acid to form salt.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The specific conductance of a $0.1\, N\, KCl$ solution at $23\,^oC$ is $0.012\, \,ohm^{-1}\,cm^{-1}$. The resistance of cell containing the solution at the same temperature was found to be $55\, ohm$. The cell constant will be ............. $\mathrm{cm}^{-1}$
→Calculate emf of cell at $25^{\circ} C$
→Cell notation : $M \left|\underset{0.01}{ M ^{2+}} \| \underset{0.0001}{ M ^{2+}}\right| M$
.........$V$ value of $E _{ Cell }^{o}$ is $4$ volt (Given $\frac{ RT }{ F }$ in $10=0.06$ )
$C{H_3}CHO + C{H_3}MgBr \to {\text{Product}}\xrightarrow{{{H_2}O}}A$ What is $A\, ?$
→The correct increasing order of basic strength for the following compounds is
In dark, which of the following reacts with hydrogen
The $EAN$ of metal atoms in $Fe(NO)_2(CO)_2$ and $CO_2(CO)_8$ respectively are
→The reaction of ethylene glycol with $P{I_3}$ gives
→Statement $I$ : Sodium hydride can be used as an oxidising agent.
→Statement $II :$ The lone pair of electrons on nitrogen in pyridine makes it basic.
Choose the CORRECT answer from the options given below:
Which one is used in the manufacture of mirror
In above reaction identify major product $(A)$ of the reaction
→