When p(x) = x^3 - 3x^2 + 4x + 32 is divided by (x + 2), the remai… - Vidyadip

Question

When $p(x) = x^3 - 3x^2 + 4x + 32$ is divided by $(x + 2),$ the remainder is:

✓

Answer

$p(x) = x^3 - 3x^2 + 4x + 32$
$x + 2 = 0 \Rightarrow x = -2$
By the renainder theorem, we know that when $p(x)$ is divided by
$(x + 2),$ the remainder is $p(-2).$
Now, $p(-2) = x^3 - 3x^2 + 4x + 32$
$= (-2)^3 - 3(-2)^2 + 4(-2) + 32$
$= -8 - 12 - 8 + 32$
$= 4$

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