MCQ
When $p(x)=x^3-a x^2+x$ is divided by $(x-a)$, the remainder is:
- A$0$
- ✓$a$
- C$2a$
- D$3a$
✓
Answer
Correct option: B.
$a$
$p(x)=x^3-a x^2+x$
$x-a=0 \Rightarrow x=a$
By the remainder theorem, we know that when $p(x)$ is divided by $(x-a)$, the remainder is $p(a)$.
Now, $p(a)=a^3-a x^2+a$
$=a^3-a^3+a$
$=a$
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