MCQ
When $p(x) = x^3 - ax^2 + x$ is divided by $(x - a),$ the remainder is:
- ✓$a$
- B$0$
- C$3a$
- D$2a$
By remainder theorem, when $p(x) = x^3 - ax^2 + x$ is divided by $(x - a),$ then the remainder $= p(a)$
Putting $x = a $ in $p(x),$ we get
$p(a) = a^3 - a × a^2 + a = ^3 - a^3 + a = a$
$\therefore$ Remainder $= a$
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