MCQ
When simplified $\Big(-\frac{1}{27}\Big)^{-\frac{2}{3}}$ is:
- A$9$
- B$-9$
- C$\frac{1}{9}$
- D$\frac{1}{9}$
✓
Answer
- $9$
Solution:
We have to find the value of $\Big(-\frac{1}{27}\Big)^{\frac{-2}{3}}$
So,
$\Big(-\frac{1}{27}\Big)^{\frac{-2}{3}}=\Big(-\frac{1}{27}\Big)^{\frac{-2}{3}}$
$=\Big(-\frac{1}{3^3}\Big)^{\frac{-2}{3}}$
$=-\frac{1}{3^{3\times\frac{-2}{3}}}$
$\Big(-\frac{1}{27}\Big)^{\frac{-2}{3}}=-\frac{1}{3^{-2}}$
$=-\frac{1}{\frac{1}{3^2}}$
$=\frac{1}{\frac{1}{9}}$
$=9$
Hence the correct choice is a.
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