MCQ
When SO2 is passed through an acidified solution of K2Cr2O7, then chromium sulphate is formed. Change in oxidation state of Cr is from.
- A+4 to +2
- B+6 to +3
- C+7 to +2
- D+5 to +3
✓
Answer
- +4 to +2
Explanation:
In acidic medium Cr is reduced from +6 to +3 as:
Cr2O7−2 + 14H+ + 6e− → 2Cr+3 + 7H2O
and SO2 is oxidised to SO3 as:
SO2 + H2O → SO3 + 2H+ + 2e−
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