Question
When sodium hydride is electrolysed, hydrogen is liberated at which electrode?

Answer

$\text{NaH}\xrightarrow{\text{electrolysis}\ \ }\text{Na}^++\text{H}^-,$
At anode: $\text{2}\text{H}^--2\text{e}^-\xrightarrow{\ \ \ \ }\text{H}_2(\text{g})$ [Loss electrons, oxidation]

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