MCQ
When sulphur is boiled with $N{a_2}S{O_3}$ solution, the compound formed is
- ASodium sulphide
- BSodium sulphate
- CSodium persulphate
- ✓Sodium thiosulphate
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$\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{{C_6}{H_5} - CH - C{H_2} - C - C{H_3}}
\end{array}\mathop {\xrightarrow{{(i)\,NaOBr}}}\limits_{(ii)\,{H_2}O/{H^ + }\,(iii)\,\Delta } $ product
product will be :
$(i)$ Diastereomers $(ii)$ Geometrical isomers
$(iii)$ Epimers $(iv)$ Anomers
$(v)$ Enantiomers