- A$15$
- B$16$
- ✓$10$
- D$8$
$=\frac{\mathrm{n}(\mathrm{n}-1)}{2}=\frac{5(5-1)}{2}=\frac{20}{2}=10 \text { lines. }$
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$2 C _{( s )}+ O _{2( g )} \rightarrow 2 CO ( g )$
When $12\,g$ carbon is burnt in $48\,g$ of oxygen, the volume of carbon monoxide produced is $......\times 10^{-1}\,L$ at STP [nearest integer]
[Given : Assume $CO$ as ideal gas, Mass of $C$ is $12\,g\,mol ^{-1}$, Mass of $O$ is $16\,g\,mol ^{-1}$ and molar volume of an ideal gas at STP is $22.7\,L\, mol ^{-1}$ ]
$(I)$ $NI_3$ $(II)$ $I_3^-$
$(III)$ $SO_3^{-2}$ $(IV)$ $NO_3^-$
Product "$A$" is :
(Round off to the Nearest Integer).
[Neglect volume change on adding $HA$. Assume degree of dissociation $<< 1]$