MCQ
When the magnetic dipole is rotated through angle `theta`, work done in rotating dipole is given by -mB cos `theta`. Now, a magnetic needle lying parallel to a magnetic field requires W units of work to tum it through 60°. What will be the value of torque needed to maintain the needle in same position?
- A0
- ✓`sqrt3` W
- C`(sqrt3//2)` W
- DW
