When two light waves each amplitude ' A ' and having a phase diff… - Vidyadip

MCQ

When two light waves each amplitude ' $A$ ' and having a phase difference of $\frac{\pi}{2}$ superimposed then the amplitude of resultant wave is

A
$\frac{A}{\sqrt{2}}$
B
$2 A$
✓
$\sqrt{2} A$
D
$\frac{A}{2}$

✓

Answer

Correct option: C.

$\sqrt{2} A$

(c) : $A_n=\sqrt{A^2+A^2+2 A^2 \cos \frac{\pi}{2}}=\sqrt{2} A$

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