MCQ
When water is heated from $0$ to $4\,^oC$
- A${C_p}\, = \,{C_v}$
- B${C_p}\, > \,{C_v}$
- ✓${C_p}\, < \,{C_v}$
- D${C_p}\, - \,{C_v}=R$
When water is heated from $0^{\circ} C$ to $4^{\circ} C$, the volume of liquid decreases.
Thus for this transition, $P \Delta V$ is negative.
$\int C_p d T=\int C_V d T+P \Delta V$
$\Rightarrow C_P < C_V$
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