MCQ
Which amide gives bromamide reaction? propanamine by Hoffmann bromamide reaction?
- ✓Butanamide
- BEthanamide
- CPropanamide
- DPentanamide
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Number of moles of $NaOH $ used in above Hoffmann bromamide reaction is
(given, $\frac{ F }{ R }=11500 K V ^{-1}$, where $F$ is the Faraday constant and $R$ is the gas constant, The value of $\ln (10)=2.30$ )
