- A$CHBr_3$
- B$CHI_3$
- ✓$CH(CN)_3$
- D$CHCl_3$
Negative charge of the conjugate base $\mathop C\limits^ - {\left( {CN} \right)_3}$ in extensively delocalized through the $C \equiv N$ group.
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$CH_3CH=CHCH_2CH(Br)CH_3$
${\Delta _r}{G^o}$ (in $kJ\,mol^{-1}$) $=120-\frac {3}{8}\,T$
The major component of the reaction mixture at $T$ is

$(I)\,C{H_3}O\mathop C\limits^ \oplus {H_2}$ is more stable than $C{H_3}\mathop C\limits^ \oplus {H_2}$
$(II)\,M{e_2}\mathop C\limits^ \oplus H$ is more stable than $C{H_3}C{H_2}\mathop C\limits^ \oplus {H_2}$
$(III)\,C{H_2} = CH - \mathop C\limits^ \oplus {H_2}$ is more stable than $C{H_3}C{H_2}\mathop C\limits^ \oplus {H_2}$
$(IV)\,C{H_2} = \mathop C\limits^ \oplus H$ is more stable than $C{H_3}\mathop C\limits^ \oplus {H_2}$
The heat of hydration of $\mathrm{CuSO}_4$ to $\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}$ is $-\mathrm{xkJ}$. The value of $\mathrm{x}$ is. . . . . . .