MCQ
Which bond angle $\theta $ gives maximum dipole moment for triatomic molecule $XY_2$
- A$\theta = {90^o}$
- ✓$\theta = {120^o}$
- C$\theta = {180^o}$
- DBoth $B$ and $C$
The dipole moment of two dipoles inclined at an angle $\theta$ is given by the equation
$\mu=\sqrt{X^2+Y^2+2 X Y \cos \theta}$
$\cos 90^{\circ}=0$. Since the angle increases from $90-180$, the value of $\cos \theta$ becomes more and more $-ve$ and hence resultant decreases. Thus, dipole moment is maximum when $\theta=90^{\circ}$
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$(I) \,C_6H_5CH_3$
$(II)\, C_6H_5COOH$
$(III)\, C_6H_6$
$(IV) \,C_6H_5NO_2$
$C{H_3} - \mathop {\mathop {CH - }\limits_{|\,\,\,\,\,\,\,} }\limits_{C{H_3}\,} C{H_2} - C{H_2} - Cl$