- ✓$\theta = {90^o}$
- B$\theta = {120^o}$
- C$\theta = {150^o}$
- D$\theta = {180^o}$
$\cos 90^o = 0$. Since the angle increases from $90 - 180$, the value of $\cos \theta $ becomes more and more $-ve$ and hence resultant decreases. Thus, dipole moment is maximum when $\theta = 90^o $.
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$I.$ one atom of oxygen
$II.$ one atom of nitrogen
$III.$ $1\times10^{-10}$ mole of oxygen
$IV.$ $1\times10^{-10}$ mole of copper
$S_2O_8^{2-} + 2e^- \longrightarrow 2SO_4^{2-}$
$Mn^{2+} + 4H_2O \longrightarrow MnO_4 + 8H^+ + 5e^-$
How many moles of $S_2O_8^{2-}$ are required to oxidise $1\, mole$ of $Mn^{ 2+}$ ?
$(a)$ The $pH$ of a mixture containing $400\, mL$ of $0.1\, M\, H_2SO_4$ and $400\, mL$ of $0.1\, M\, NaOH$ will be approximately $1.3$.
$(b)$ Ionic product of water is temperature dependent.
$(c)$ A monobasic acid with $K_a = 10^{-5}$ has a $pH = 5$. the degree of dissociation of this acid is $50\%$.
$(d)$ The Le Chatelier’s principle is not applicable to common-ion effect.
The correct statements are: