MCQ
Which bonds are formed by a carbon atom with $sp^2$ -hybridisation?
- A$4\,\pi$ -bonds
- B$2\,\pi$ -bonds and $2\, \sigma$ - bonds
- C$1\,\pi$ -bonds and $3\, \sigma$-bonds
- D$4\,\sigma$ -bonds
✓
Answer
$(c)$ By $sp^2-$ hybridisation.
Hybridisation orbital $= 3 [3\,\sigma$ -bonds] Unhydrised orbital $= 1$ [$1\, \pi$ -bond]
Hybridisation orbital $= 3 [3\,\sigma$ -bonds] Unhydrised orbital $= 1$ [$1\, \pi$ -bond]
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