MCQ
Which cell will measure standard electrode potential of copper electrode?
  • A
    $\text{Pt}(\text{s})\big|\text{H}_2(\text{g},0.1\text{ bar})\big|\text{H}^+(\text{aq}.1\text{M})\big|\big|\text{Cu}^{2+}(\text{aq.1})\text{M}\big|\text{Cu}$
  • B
    $\text{Pt}(\text{s})\big|\text{H}_2(\text{g},1\text{ bar})\big|\text{H}^+(\text{aq}.1\text{M})\big|\big|\text{Cu}^{2+}(\text{aq.2})\text{M}\big|\text{Cu}$
  • $\text{Pt}(\text{s})\big|\text{H}_2(\text{g},1\text{ bar})\big|\text{H}^+(\text{aq}.1\text{M})\big|\big|\text{Cu}^{2+}(\text{aq.1})\text{M}\big|\text{Cu}$
  • D
    $\text{Pt}(\text{s})\big|\text{H}_2(\text{g},1\text{ bar})\big|\text{H}^+(\text{aq}.0.1\text{M})\big|\big|\text{Cu}^{2+}(\text{aq.1})\text{M}\big|\text{Cu}$

Answer

Correct option: C.
$\text{Pt}(\text{s})\big|\text{H}_2(\text{g},1\text{ bar})\big|\text{H}^+(\text{aq}.1\text{M})\big|\big|\text{Cu}^{2+}(\text{aq.1})\text{M}\big|\text{Cu}$
When copper electrode is connected to standard hydrogen electrode, it acts as cathode and its standard electrode potential can be measured.
$\text{E}^0=\text{E}^0_\text{R}-\text{E}^0_\text{L}=\text{E}^0_\text{R}-0=\text{E}^0_\text{R}$
$\text{Pt}(\text{s})\big|\text{H}_2(\text{g},1\text{ bar})\big|\text{H}^+(\text{aq}.1\text{M})\big|\big|\text{Cu}^{2+}(\text{aq.1})\text{M}\big|\text{Cu}$ will measure standard electrode potential of copper electrode.
To calculate the standard electrode potential of the given cell it is coupled with the standard hydrogen electrode in which pressure of hydrogen gas is one bar and the cone, of $H^+$ ion in the solution is one molar and also the concentrations of the oxidized and the reduced forms of the species in the right hand half$-$cell are unity.

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