Which combination gives maximum number of products ?

MCQ

✓

Answer

Correct option: C.

$XeF_4+H_2O$

c
$(a)$ $\mathrm{P}_{4}+\mathrm{SOCl}_{2} \rightarrow \rightarrow \mathrm{PCl}_{3}+\mathrm{SO}_{2}+\mathrm{S}_{2} \mathrm{Cl}_{2}$

$(b)$ $P_{4}+S O_{2} C l_{2} \longrightarrow P Cl_{5}+S O_{2}$

$(c)$ $\mathrm{XeF}_{4}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{Xe}+\mathrm{XeO}_{3}+\mathrm{HF}+\mathrm{O}_{2}$

$(d)$ $N H_{4} N O_{3}+Z n+\,e x c e s s\, N a O H \longrightarrow N H_{3} \uparrow+N a Zn O_{2}+H_{2} O$

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$(A)$ $NH _4 NO _3$ $(B)$ $\left( NH _4\right)_2 Cr _2 O _7$ $(C)$ $Ba \left( N _3\right)_2$ $(D)$ $Mg _3 N _2$

($A$) a high activation energy usually implies a fast reaction.

($B$) rate constant increases with increase in temperature. This is due to a greater number of collisions whose energy exceeds the activation energy.

($C$) higher the magnitude of activation energy, stronger is the temperature dependence of the rate constant.

($D$) the pre-exponential factor is a measure of the rate at which collisions occur, irrespective of their energy.