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STD 12 - p -Block elements - ll — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 - p -Block elements - ll4 Marks
MCQ
Which compound acts as an oxidising as well as reducing agent
  • ✓
    $S{O_2}$
  • B
    $KMn{O_4}$
  • C
    $A{l_2}{O_3}$
  • D
    $Cr{O_3}$
✓

Answer

Correct option: A.
$S{O_2}$
a
(a) The minimum and maximum oxidation number of $S$ are $-2$ and $+6$ respectively. Since the oxidation number of $S$ in $S{O_2}$ is $+4$, therefore it can be either increased or decreased.

Therefore $S{O_2}$ behaves both as an oxidising as well as reducing agent.

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$\mathop {\mathop C\limits^ \oplus  {H_3}}\limits_{(a)} $ $\mathop {\begin{array}{*{20}{c}}
  {C{H_2} - \mathop C\limits^ \oplus  {H_2}} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {\,F\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}}\limits_{(b)} $ $\mathop {\begin{array}{*{20}{c}}
  {C{H_2} - \mathop C\limits^ \oplus  {H_2}} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}}\limits_{(c)} $ $\mathop {\begin{array}{*{20}{c}}
  {C{H_2} - \mathop C\limits^ \oplus  {H_2}} \\ 
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