STD 12 - 10. Biomolecules — NEET STD 11 Science — Question

${{C}_{2}}{{H}_{5}}N{{H}_{2}} \xrightarrow{HN{{O}_{2}}}A \xrightarrow{PC{{l}_{5}}}B \xrightarrow{H.N{{H}_{2}}}C$

${N_2}{O_4}(g) \rightleftharpoons 2N{O_2}(g),\,\,\frac{{{K_c}}}{{{K_p}}}$ is

$M \mid M ^{2+}$ (saturated solution of a sparingly soluble salt, $\left.MX _2\right) \| M ^{2+}\left(0.001\right.$ mol dm $\left.d ^{-3}\right) \| M$ The emf of the cell depends on the difference in concetration of $M ^{2+}$ ions at the two electrodes. The emf of the cell at $298$ is $0.059 \ V$

$1.$ The solubility product $\left( K _{ sp } ; mol ^3 dm ^{-9}\right)$ of $MX _2$ at $298$ based on the information available the given concentration cell is (take $2.303 \times R \times 298 / F =0.059 \ V$ )

$(A)$ $1 \times 10^{-15}$ $(B)$ $4 \times 10^{-15}$

$(C)$ $1 \times 10^{-12}$ $(D)$ $4 \times 10^{-12}$

$2.$ The value of $\Delta G \left( kJ \ mol ^{-1}\right)$ for the given cell is (take $1 F =96500 \ C \ mol ^{-1}$ )

$(A)$ $-5.7$ $(B)$ $5.7$ $(C)$ $11.4$ $(D)$ $-11.4$

Give the answer question $1$ and $2.$