- A$HF$
- B$HCl$
- C$HBr$
- ✓$HI$
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$(I)$ $S_2O_4^{2-}$ $(II)$ $S_2O_5^{2-}$ $(III)$ $S_2O_6^{2-}$

$\begin{matrix}
\begin{matrix}
C{{H}_{3}}\,\,\,\,\,\,\,\, \,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\end{matrix} \\
C{{H}_{3}}-C-CH=C{{H}_{2}} \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,\,\,\,\,\, \,\,\,\, \\
\end{matrix}\,$ $\xrightarrow{{{H}_{2}}O/{{H}^{\oplus }}}$ $\underset{Major\,\,product}{\mathop{A}}\,$ $+$ $\underset{Major\,\,product}{\mathop{B}}\,$
The major product is
| Column $-I$ (various solutions) | Column $-II$ (Their freezing point ) | ||
| $a$ | $0.1\,M\, BaCl_2$ solution | $p$ | $271\,K$ |
| $b$ | $0.1\,M\, NaCl$ solution | $q$ | $270\, K$ |
| $c$ | $0.1\,M\, K_3 [Fe(CN)_6]$ solution | $r$ | $268\, K$ |
| $d$ | $0.1\,M\, Al_2 (SO_4)_3$ solution | $s$ | $269\, K$ |
Given : Freezing point of $0.1\,M$ sucrose solution $= 272\,K$ and $F.pt.$ of water $= 273\,K$
Which of the following option show correct matches ? (assume, molarity=molality)