- A${F^ - }$
- B$B^{3+}$
- ✓$O^{2-}$
- D$Li^+$
No. of electrons in $B ^{3+}=8$
No. of electrons in $Li ^{+}=4$
No. of electrons in $F ^{-}=10$
$F ^{-}$and $O ^{2-}$ have highest no. of electrons, thus the effective nuclear charge
$\{\left.\frac{\text { nuclear charge }}{\text { No. of electrons }}\right\}$ for them is less than $B$ and $Li$.
When effective nuclear charge increases, size of an ion decreases.
Amongst $F ^{-}$and $O ^{2-}$, size of $O ^{2-}$ is more than $F ^{-}$as size decreases on moving from left to right in a period.
Therefore, $O ^{2-}$ is largest in size.
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$(A)$ $M$ and $N$ are non-mirror image stereoisomers
$(B)$ $M$ and $O$ are identical
$(C)$ $M$ and $P$ are enantiomers
$(D)$ $M$ and $Q$ are identical
${\text{2PQ}} \rightleftharpoons {{\text{P}}_2}{\text{ + }}{{\text{Q}}_2}\,;\,\,\,\,{{\text{K}}_1}{\text{ = 2}}{\text{.5 }} \times \,{\text{1}}{{\text{0}}^5}\,$
${\text{PQ + }}\frac{1}{2}{R_2} \rightleftharpoons PQR\,;\,\,\,\,{{\text{K}}_2}{\text{ = 5 }} \times \,{\text{1}}{{\text{0}}^{ - 3}}\,$
The value of equilibrium constant for reaction
$\frac{1}{2}{{\text{P}}_2}{\text{ + }}\frac{1}{2}{{\text{Q}}_2}{\text{ + }}\frac{1}{2}{R_2} \rightleftharpoons PQR\,$ is
Assertion $A$: In the photoelectric effect, the electrons are ejected from the metal surface as soon as the beam of light of frequency greater than threshold frequency strikes the surface.
Reason $R$ : When the photon of any energy strikes an electron in the atom, transfer of energy from the photon to the electron takes place.
In the light of the above statements, choose the most appropriate answer from the options given below :