Question
Which ion has largest radius
So, $r \propto \frac{e^{-}}{p}$
Hence, $r = se ^{2-}\,>\, Rb ^{+}$
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$Hex - 3 - ynal\xrightarrow[\begin{subarray}{l}
(ii)\,PB{r_3} \\
(i)\,Mg/ether \\
(i)\,C{O_2}/{H_3}{O^ + }
\end{subarray} ]{{(i)\,NaB{H_4}}}\,?$
${H_2}{O_2}\xrightarrow{{R.T}}{H_2}O + \frac{1}{2}{O_2}$
$Hg_2^{2 + } \to \,H{g^{2 + }}+ Hg\left( l \right)$