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$(i)$ $\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{C{H_3} - {C^ \mathbf{-} }} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
$(ii)$ $H _{2} C = CH - CH _{2}$
$(iii)$ $HC \equiv \stackrel{\ominus}{ C }$
$(iv)$ $\stackrel{\ominus}{ CH _{3}}$
$(v)$ $\stackrel{\ominus}{{ }_{ CN }}$
$CaCO _{3}( s ) \rightarrow CaO ( s )+ CO _{2}( g )$ the values of $\Delta H ^{\circ}$ and $\Delta S^{\circ}$ are $+179.1 kJ mol ^{-1}$ and $160.2\,J / K$ respectively at $298 \,K$ and $1 \,bar$. Assuming that $\Delta H ^{\circ}$ and $\Delta S ^{\circ}$ do not change with temperature, temperature above which conversion of lime-stone to lime will be spontaneous is ........... $K$
$(I)$ Acetic acid $(II)\, o-$ nitrophenol $(III)\, m-$ nitrophenol $(IV)\, o-$ boric acid
Select correct alternate
