Question
Which is a stronger reducing agent $Cr^{2+}$ or $Fe^{2+}$ and why?

Answer

$Cr^{2+}$ is a stronger reducing agent than $Fe^{2+}.$
This is because $E^\circ(Cr^{3+}/Cr^{2+})$ is negative $(-0.41\ V)$
whereas $E^\circ(Fe^{3+}/Fe^{2+})$ is positive (+ 0.77 V).
Thus, $Cr^{2+}$ is easily oxidised to $Fe^{3+}$ but $Fe^{2+}$ cannot be easily oxidised to $Fe^{3+}.$

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