MCQ
Which is correct oxidation state of lead
- ✓$+ 2$, $+ 4$
- B$+ 1$, $+ 2$
- C$+ 3$, $+ 4$
- D$4$
$+2$ oxidation state which is lower oxidation state due to inert pair effect(stable oxidation state for lead).
$+4$ oxidation state which is Higher oxidation state
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$CH_3 - CH = CH - CH_3 \xrightarrow{{{O_3}}} A $$\xrightarrow[{Zn}]{{{H_2}O}} B.$
The compound $B$ is
Phenol $(C_6H_6O)$ $\xrightarrow{{B{r_2}\,\,in\,\,H_2{O}}}$ $Y$ (Major product)
What is $X$ and $Y$ in above reaction respectively
| $I.P.$ | Reason |
| $(A)$ $N > O$ | Half filled configuration |
| $(B)$ $Zr < Hf$ | Lanthenide contraction |
| $(C)$ $Na > K$ | $Z_{eff}$ |
| $(D)$ $Al < Ga$ | Transition contraction |

$2 Al + 3MnO \to Al_2O_3 + 3Mn$
Which of the following is correct? (Atomic weights of $Mn = 55$ and $Al = 27$)