Question
Which is greater in$\frac{-5}{6}, \frac{-4}{3}$
✓
Answer
To find the greater rational number we need to have a common denominator of $6$ and $3$, so $LCM$ of $6$ and $3$ is $6$
$\frac{-5}{6}=\frac{-5}{6}$
$\frac{-4}{3}=\frac{-4 \times 2}{3 \times 2}=\frac{-8}{6}. . . .[LCM (6,3) = 6]$
$\because$$\frac{-5}{6}>\frac{-8}{6}$
$\frac{-5}{6}>\frac{-4}{3}$
Or
$-5\over 6$ and $-4\over 3$
cross multiplying the numerators we have
$-5 \times 3$ and $-4 \times 6$
$-15 > -24$
$\therefore$ $-5\over 6$>$-4\over 3$
$\frac{-5}{6}=\frac{-5}{6}$
$\frac{-4}{3}=\frac{-4 \times 2}{3 \times 2}=\frac{-8}{6}. . . .[LCM (6,3) = 6]$
$\because$$\frac{-5}{6}>\frac{-8}{6}$
$\frac{-5}{6}>\frac{-4}{3}$
Or
$-5\over 6$ and $-4\over 3$
cross multiplying the numerators we have
$-5 \times 3$ and $-4 \times 6$
$-15 > -24$
$\therefore$ $-5\over 6$>$-4\over 3$
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