- ✓$CsBr_3 \rightleftharpoons Cs^+ + Br^-$
- B$I_4O_9 \rightleftharpoons I^{3+} + (IO_3^-)_3$
- C$AgBrO_3 \rightleftharpoons Ag^+ + BrO_3^-$
- D$I_2O_4 \rightleftharpoons IO_2^- + IO_2^+$
$(C)$ $\theta_3 > \theta_2 > \theta_1$
$(D)$ Total $20$ unshared lone pairs are present
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$trans-3$ -hexene $\xrightarrow{(b)}$ meso $3,4-$ hexanediol
Choose pair of reagent $(a, b)$ for above conversions
${H_2}{O_2}\xrightarrow{{R.T}}{H_2}O + \frac{1}{2}{O_2}$
$\begin{array}{*{20}{c}}
{\,\,\,\,\,C{H_3}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,\,\,\,\,{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} O{\mkern 1mu} } \\
{\,\,\,|{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,\,\,\,\,\,\,\,\,\,{\mkern 1mu} {\mkern 1mu} ||} \\
{C{H_3} - CH - C - OH}
\end{array}$ $+ C{H_3} - N{H_2} \to 'A'\xrightarrow[\Delta ]{}'B'\xrightarrow{\begin{subarray}{l}
{\text{LiAl}}{{\text{H}}_4} \\
{\text{(excess)}}
\end{subarray} }'C'$
The final product $‘C’$ will be