MCQ
Which is not a colligative property
- ✓Refractive index
- BLowering of vapour pressure
- CDepression of freezing point
- DElevation of boiling point
✓
Answer
Correct option: A.
Refractive index
a
Colligative properties depend on how many solute particles are present as well as the solvent amount, but they do NOT depend on the type of solute particles.
Colligative properties depend on how many solute particles are present as well as the solvent amount, but they do NOT depend on the type of solute particles.
Hence, Refractive Index is not a colligative particles as it only depends on nature of materials.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Chloride of an element $A$ gives neutral solution in water. In the periodic table, the element $A$ belongs to
→Clemmensen reduction of a ketone is carried out in the presence of
Ozonolysis of which one of the following compounds produces acetone and $2-$ pentanone
→How does the energy gap between successive energy levels in an atom vary from low to high $n$ values?
→$\Delta {H^o}$ combustion of $C_4H_{10}(g)$ is $-2650\, kJ\, mol^{-1}$ the amount of heat evolve at constant pressure that can be obtained by burning $5.8\, kg$ of $C_4H_{10}$ is approx
→An aqueous solution containing $28\%$ by mass of a liquid (mol. mass $= 140$) has a vapour pressure of $160\ mm$ at $37\,^oC$. Find the vapour pressure of the pure liquid $A$ approximately .......... $mm$ . (The vapour pressure of water at $37\,^oC$ is $150\ mm$)
→Which of these do not undergo Wurtz reaction
If the velocity of hydrogen molecule is $5 \times {10^4}\,cm\,se{c^{ - 1}}$, then its de-Broglie wavelength is ............. $\mathop {\rm{A}}\limits^{\rm{o}} $
→In the reaction given below
The compound $\begin{matrix}
C{{H}_{3\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}} \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}-C=CH-C{{H}_{3}} \\
\end{matrix}$ on reaction with $NaIO_4$ in the presence of $KMnO_4$ gives :-
→C{{H}_{3\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}} \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}-C=CH-C{{H}_{3}} \\
\end{matrix}$ on reaction with $NaIO_4$ in the presence of $KMnO_4$ gives :-