- ✓Refractive index
- BLowering of vapour pressure
- CDepression of freezing point
- DElevation of boiling point
Hence, Refractive Index is not a colligative particles as it only depends on nature of materials.
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$\left[\right.$ Given : $K _{ sp }( AgBr )=4.9 \times 10^{-13}$ at $298 K$
$\lambda_{ Ag ^{+}}^0=6 \times 10^{-3} Sm ^2\,mol ^{-1}$
$\lambda_{ Br ^{-}}^0=8 \times 10^{-3} Sm ^2\,mol ^{-1}$
$\left.\lambda_{ NO _3^{-}}^0=7 \times 10^{-3} Sm ^2\,mol ^{-1}\right]$
$T{i^{4 + }} + e \to T{i^{3 + }},\,{E^o} = - xV$,
$F{e^{3 + }} + e \to F{e^{2 + }},\,{E^o} = - yV$,
$\{$ where $x < y$ point out the wrong statement

(Given: Atomic no. $Eu, 63; Sm , 62 ; Tm , 69 ; Tb$, $65 ; Yb , 70 ; Dy , 66]$
${\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+},\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+},\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+},}$
${\left[\mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+},\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}}$
