- AButane $-2-$ ol
- ✓Butane $-1-$ ol
- CPropane $-2-$ ol
- DIsopropyl alcohol
From the picture, we can conclude that butan$-1-$ol is primary alcohol as $- OH$ group connected to a primary carbon. Rest are secondary alcohol as $- OH$ group is connected to a secondary carbon atom(carbon atom connected to further two carbon atom).
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$(i)\,\,C\,({\rm{graphite}})\, + \,{O_2}{\kern 1pt} (g)\, \to \,C{O_2}\,(g);\,\Delta r{H^\circleddash} = x\,\,kJ\,mo{l^{ - 1}}$
$(ii)\,\,C\,({\rm{graphite}})\, + \,\frac{1}{2}{O_2}{\kern 1pt} (g)\, \to \,CO\,(g);\,\Delta r{H^\circleddash} = y\,\,kJ\,mo{l^{ - 1}}$
$(iii)\,\,CO\,(g)\, + \,\frac{1}{2}{O_2}{\kern 1pt} (g)\, \to \,C{O_2}\,(g);\,\Delta r{H^\circleddash} = z\,\,kJ\,mo{l^{ - 1}}$
Based on the above thermochemical equations, find out which one of the following algebraic relationships is correct?