MCQ
Which is the $CORRECT$ relation of bond angles?
- A$NH_3 > (CH_3)_3N > (SiH_3)_3N$
- ✓$(SiH_3)_3N > (CH_3)_3N > NH_3$
- C$NH_3 > (SiH_3)_3N > (CH_3)_3N$
- D$(CH_3)_3N > (SiH_3)_3N > NH_3$
$\left(\mathrm{CH}_{3}\right)_{3} \mathrm{N} \quad \mathrm{sp}^{3}: 108^{o}$ -bulky have more
repulsion than smaller $H$
$-\left(\mathrm{SiH}_{3}\right)_{3} \mathrm{N} \cdot \mathrm{sp}^{2}: 120^{o}\, \mathrm{LP}$ of $\mathrm{N}$ engages in back
bonding with empty $d$ orbitals of $Si$
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$(i)$ ${C_6}{H_5}{N^ + } \equiv NC{l^ - }$ $(ii)$ ${C_6}{H_5}{N^ + } \equiv N$
$(iii)$ ${{\overset{\centerdot }{\mathop{C}}\,}_{6}}{{H}_{5}}$ $(iv)$ $C_6H_5Cl$
Given : $K_f (H_2O)$ = $2\ K\ kg\ mole^{-1}$, $K_{sp} (PbCl_2)$ = $4 × 10^{-6}$
(Assume molarity to be equal to molality) .....$^oC$
$I.\, Al_2Cl_6\,\,\, II.\, B_2H_6\,\,\, III.\, Fe_2Cl_6\,\,\, IV.\, Si_2H_6$