MCQ
Which is the most explosive
- ✓$NC{l_3}$
- B$PC{l_3}$
- C$AsC{l_3}$
- DAll of these
✓
Answer
Correct option: A.
$NC{l_3}$
a
(a) $NC{l_3}$ is highly reactive and unstable. Hence it is explosive.
(a) $NC{l_3}$ is highly reactive and unstable. Hence it is explosive.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
An unknown chlorohydrocarbon has $3.55\%$ of chlorine. If each molecule of the hydrocarbon has one chlorine atom only, chlorine atoms present in $1\,g$ of chlorohydrocarbon are (Atomic wt. of $Cl = 35.5\,u;$ Avogadro constant $= 6.023 \times 10^{23}\,mol^{- 1}$ )
→Which of the following compounds represents acrylonitrile
Which of following is amphoteric
In the given reaction $\begin{array}{*{20}{c}}
{{C_6}{H_5} - C - C{H_3}} \\
{||} \\
O
\end{array}$ $\xrightarrow{{N{H_2}OH/{H^ \oplus }}}X\xrightarrow{{Na/{C_2}{H_5}OH}}Y$. $Y$will be
→{{C_6}{H_5} - C - C{H_3}} \\
{||} \\
O
\end{array}$ $\xrightarrow{{N{H_2}OH/{H^ \oplus }}}X\xrightarrow{{Na/{C_2}{H_5}OH}}Y$. $Y$will be
Molar mass of the hydrocarbon $(X)$ which on ozonolysis consumes one mole of $O _3$ per mole of $( X )$ and gives one mole each of ethanal and propanone is $......g\,mol ^{-1}$ (Molar mass of $C : 12\,g\,mol ^{-1}, H : 1\,g\,mol ^{-1}$ )
→Compound $(B)$ is
→$MeO$ The compound $(X)$ is
→The formation of the oxide ion, ${O^{2 - }}\left( g \right)$, from oxygen atom requires first an exothermic and then an endothermic step as shown below
→$O\left( g \right) + {e^ - } \to O_{\left( g \right)}^ - \,\,\,\,;\,\,\,\,{\Delta _f}{H^\Theta } = - 141\,kJ\,mo{l^{ - 1}}$
${O^ - }\left( g \right) + {e^ - } \to O_{\left( g \right)}^{2 - }\,\,\,\,;\,\,\,\,{\Delta _f}{H^\Theta } = + 780\,kJ\,mo{l^{ - 1}}$
Thus process of formation of $O_2^-$ in gas phase is unfavourable even thought $O_2^-$ is isoelectronic with neon. It is due to the fact that,
The correct order of increasing $s$ -character (in percentage) in the hybrid orbitals of following molecules ions is :-
$(I)$ $CO_3^{2-}$ $(II)$ $XeF_4$
$(III)$ $I_3^-$ $(IV)$ $NCl_3$
$(V)$ $BeCl_2$
→$(I)$ $CO_3^{2-}$ $(II)$ $XeF_4$
$(III)$ $I_3^-$ $(IV)$ $NCl_3$
$(V)$ $BeCl_2$
The reaction sequence($s$) that would lead to $o$-xylene as the major product is (are)
→