Question
Which $L$ -sugar on oxidation gives an optically active dibasic acid
✓
Answer
a
Any sugar will be optically active when it does not have any plane of symmetry.
Any sugar will be optically active when it does not have any plane of symmetry.
As only $(a)$ and $(d)$ are $L$-sugar, $(b)$ and $(c)$ are $D$-sugar after oxidation.
$(a)$ (Refer to Image $1$)
As the product do not superimpose in its mirror image.
$(d)$ (Refer to Image $2$)
As it has plane of symmetry.
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