Which of following can show optical isomerism - Vidyadip

MCQ

Which of following can show optical isomerism

A
$CuSO_4 . 5H_2O$
✓
$K_3[Cr(C_2O_4)_3]$
C
$K_3 [Fe(CN)_6]$
D
$[Cr(NH_3)_6]Cl_3$

✓

Answer

Correct option: B.

$K_3[Cr(C_2O_4)_3]$

b
Only $K _3\left[ Cr \left( C _2 O _4\right)_3\right]$ shows optical isomerism.

Other compounds have symmetry so they are not able to show optical isomerism.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 5. Co-ordination chemistry→5. Co-ordination chemistry — all question types→Chemistry STD 12 Science question papers→CBSE Board STD 12 Science question papers→CBSE Board question paper generator→

Similar questions

What is tested in the urine of a diabetes patient?

The normal $f.p.$ of nitrobenzene is $278.82\, K$. If a non-volatile solute is dissolved in it and a solution of $0.25$ molality is prepared. The observed $f.p.$ of the solution is $276.82\, K$. Evaluate $K_f$ of nitrobenzene ............ $K\,Kg\,mol{e^{ - 1}}$.

For a first order reaction velocity constant, $K = {10^{ - 3}}{s^{ - 1}}$. Two third life for it would be ........... $\sec$

${C_2}{H_5}CHO$ and ${(C{H_3})_2}CO$ can be distinguished by testing with

$Cu^{+2} + 2e^-\to Cu$ , $E^o = X_1$

$Cu^+ + e^-\to Cu$, $E^o = X_2$

Calculate $E^o$ for $Cu^{+2} + e^-\to Cu^+$

$C{H_3}C{O_2}Et + {(C{H_2})_5}{(MgBr)_2}\xrightarrow[{(2){H^ + }}]{}\mathop {{C_7}{H_{14}}O}\limits_{(A)} $ ; compound $(A)$ will be

Identify the incorrect statement with respect to ozone

The oxide of metal $R$ can be reduced by the metal $P$ and metal $R$ can reduce the oxide of metal $Q.$ Then the decreasing order of the reactivity of metal $P, Q$ and $R$ with oxygen is:

Ethyl bromide on boiling with alcoholic solutions of sodium hydroxide forms:

$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,HOC{H_2}} \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|
\end{array}} \\
{{H_2}C = CH - C{H_2} - C{H_2} - C - OH} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_2} - C{H_3}}
\end{array}$ $\xrightarrow[{TsOH}]{{\begin{array}{*{20}{c}}
O \\
{||} \\
{C{H_3} - C - C{H_3}}
\end{array}}}(A)$ $\xrightarrow[{{{(C{H_3})}_2}S}]{{{O_3}}}(B) + HCHO$ Product $(B)$ is