$NO^-_3, CO^{2-}_3 ,CO^-_3 ,SO_3$
- A$NO_3^- , CO^{2-}_3$
- B$SO_3 , NO_3^-$
- C$ClO_3^- , CO^{2-}_3$
- D$CO^{2-}_3, ClO_3^-$
$NO^-_3, CO^{2-}_3 ,CO^-_3 ,SO_3$
$\mathrm{NO}_{3}^{-}=32 \mathrm{e}^{-}$
$\begin{array}{l}\mathrm{CO}_{3}^{2-}=32 \mathrm{e}^{-} \\\mathrm{ClO}_{3}^{-}=42\mathrm{e}^{-}\end{array}$
$\mathrm{SO}_{3}^{-}=41 \mathrm{e}^{-}$
Therefore, $\mathrm{NO}_{3}^{-}$ and $\mathrm{CO}_{3}^{2-}$ are isoelectronic The structures of both $\mathrm{NO}_{3}^{-}$ and $\mathrm{CO}_{3}^{2-}$ is trigonal planar. Therefore $\mathrm{NO}_{3}^{-}$ and $\mathrm{CO}_{3}^{2-}$ are isostructural also.
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(Given ${\Delta _{fus}}H = 6\, kJ\, mol^{-1}$ at $0\,^oC$,
$C_p(H_2O, l) =75.3\, J\, mol^{-1} \, K^{-1}$ ,
$C_p(H_2O, s) = 36.8\, J\, mol^{-1} \, K^{ -1}$ )
