Question
Which of the following are perfect cube?3087
✓
Answer
On factorising 3087 into prime factors, we get
3087 = 3 × 3 × 7 × 7 × 7
Group the factors in triples of equal factors as:
3087 = 3 × 3 × {7 × 7 × 7}
It is evident that the prime factors of 3087 can be grouped into triples of equal factors and no factor is left over.
Therefore, 243 is a perfect cube.
3087 = 3 × 3 × 7 × 7 × 7
Group the factors in triples of equal factors as:
3087 = 3 × 3 × {7 × 7 × 7}
It is evident that the prime factors of 3087 can be grouped into triples of equal factors and no factor is left over.
Therefore, 243 is a perfect cube.
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