Question
Which of the following are perfect cube?4608

Answer

On factorising 3087 into prime factors, we get
4608 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3
Group the factors in triples of equal factors as:
4608 = {2 × 2 × 2} × {2 × 2 × 2} × {2 × 2 × 2} × 3 × 3
It is evident that the prime factors of 4608 can be grouped into triples of equal factors and no factor is left over.
Therefore, 4608 is a perfect cube.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free