- A$O^-$
- ✓$S^-$
- C$Se^-$
- D$Te^-$
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$2 {X}+\mathrm{B}_2 \mathrm{H}_6 \rightarrow\left\lfloor\mathrm{BH}_2(\mathbf{X})_2\right\rfloor^{+}\left\lfloor\mathrm{BH}_4\right]^{-}$ the amine(s) ${X}$ is$(are)$
$(A)$ $\mathrm{NH}_3$ $(B)$ $\mathrm{CH}_3 \mathrm{NH}_2$ $(C)$ $\left(\mathrm{CH}_3\right)_2 \mathrm{NH}$ $(D)$ $\left(\mathrm{CH}_3\right)_3 \mathrm{~N}$
| Reaction | Product | |
| $I$ | $RX + AgCN$ | $RNC$ |
| $II$ | $RX + KCN$ | $RCN$ |
| $III$ | $RX + KNO_2$ | (image) |
| $IV$ | $RX + AgNO_2$ | $R-O-N = O$ |

$\mathrm{BrO}_{4}^{-} \stackrel{1.82 \mathrm{V}}{\longrightarrow} \mathrm{BrO}_{3}^{-} \stackrel{1.5 \mathrm{V}}{\longrightarrow} \mathrm{HBrO}$$\stackrel{1.0652 \mathrm{V}}{\longrightarrow} \mathrm{Br}_{2} \stackrel{1.595 \mathrm{V}}{\longrightarrow} \mathrm{Br}^{-}$
Then the species undergoing disproportionation is