MCQ
Which of the following can not react with Bayer's reagent
- ✓Benzene
- BAllyl chloride
- CAcetylene
- D$(A)$ and $(B)$ Both
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$C_{(graphite)} +O_2(g) \rightarrow CO_2(g)\,;$
$\Delta _rH^o=-395.5 \, kJ\,mol^{-1}$
$H_2 (g) + \frac{1}{2} O_2 (g) \rightarrow H_2O(l)\,;$ $\Delta _rH^o =-285.8\, kJ\, mol^{-1}$
$CO_2(g) + 2H_2O(l) \rightarrow CH_4(g) + 2O_2(g)\,;$
$\Delta _rH^o = + 890.3\, kJ\, mol^{-1}$
Based on the above thermochemical equations, the value of, $\Delta _rH^o $ at $298\, K$ for the reaction
$C_{(graphite)} + 2H_2(g) \rightarrow CH_4(g) $ will be for $\Delta_{r} H^{\circ}$ ........... $kJ \,mol^{-1}$
| list $I$ (species) | list $II$ ( $O-N-O$ angle) |
| $(A)$ $NO_2^+$ | $(1)$ $180^o$ |
| $(B)$ $NO_2$ | $(2)$ $132^o$ |
| $(C)$ $NO_2^-$ | $(3)$ $120^o$ |
| $(D)$ $NO_3^-$ | $(4)$ $115^o$ |
| $(5)$ $109^o$ |