MCQ
Which of the following cannot be explained by crystal field theory?
- AThe order of spectrochemical series
- BMagnetic properties of transition metal complexes
- CColour of metal complexes
- ✓Stability of metal complexes
✓
Answer
Correct option: D.
Stability of metal complexes
d
Crystal field theory introduce spectrochemical series based upon the experimental values of $\Delta$ but can't explain it's order. While other three points are explained by $CFT$. Specially when the $CFSE$ increases thermodynamic stability of the complex increases.
Crystal field theory introduce spectrochemical series based upon the experimental values of $\Delta$ but can't explain it's order. While other three points are explained by $CFT$. Specially when the $CFSE$ increases thermodynamic stability of the complex increases.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
If the magnetic moment of ${\left[ {Ag{{\left( {CN} \right)}_2}} \right]^{ - 1}}$ is zero, then the number of unpaired electrons will be
→What is the correct order of reactivity of alcohols in the following reaction?
$\text{R}-\text{OH}+\text{HCL}\xrightarrow{\text{ZnCl}_2}\text{R}-\text{Cl}+\text{H}_2\text{O}$
→$\text{R}-\text{OH}+\text{HCL}\xrightarrow{\text{ZnCl}_2}\text{R}-\text{Cl}+\text{H}_2\text{O}$
A lanthanoid has $'n'$ unpaired electrons and another lanthanoid has $(14-n)$ unpaired electrons. It means
→The correct order of ionic radii of ${Y^{3 - }},L{a^{3 + }},E{u^{3 + }}$ and $L{u^{3 + }}$ is
→(Atomic No. $Y = 39$, $La = 57$, $Eu = 63$, $Lu = 71$)
Which of the following metal on burning in moist air does not give smell of ammonia?
Among the following which one does not act as an intermediate in Hofmann rearrangement
For the reaction, $3A+2B \to C + D$, the differential rate law can be written as
→Total No. of stereoisomers of $B$ are ?
→Match List $I$ with List $II$
→| List $I$ Oxide | List $II$ Type of Bond |
| $A$ $N _2 O _4$ | $I$. $1 N = O$ bond |
| $B$ $NO _2$ | $II$. $1 N - O - N$ bond |
| $C$ $N _2 O _5$ | $III$. $1 N - N$ bond |
| $D$ $N _2 O$ | $IV$. $1 N = N / N \equiv N$ bond |
Choose the correct answer from the options given below:
In photography sodium thiosulphate is used as