Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$P =\left[ FeF _6\right]^{3-}, Q =\left[ V \left( H _2 O \right)_6\right]^{2+} \text { and } R =\left[ Fe \left( H _2 O \right)_6\right]^{2+} \text {. }$
The correct order of the complex ions, according to their spin-only magnetic moment values (in $B.M.$) is
Which of the following statements are correct about the mechanism of this reaction?
$F{e^{ + 3}}\left( {aq} \right) + {e^ - } \to F{e^{2 + }}\left( {aq} \right);{E^o} = + 0.77\,V$
$A{l^{ + 3}}\left( {aq} \right) + 3{e^ - } \to Al\left( s \right);{E^o} = - 1.66\,V$
$B{r_2}\left( {aq} \right) + 2{e^ - } \to 2B{r^ - };{E^o} = + 1.09\,V$
Considering the electrode potentials, which of the following represents the correct order of reducing power?
$\mathrm{A} \stackrel{700 \mathrm{K}}{\rightarrow}$ Product
$\mathrm{A}\xrightarrow[\text { catalyst }]{500 \mathrm{K}} $ Product
it was found that $\mathrm{E}_{\mathrm{a}}$ is decreased by $30 \;\mathrm{kJ} / \mathrm{mol}$ in the presence of catalyst.
If the rate remains unchanged, the activation energy for catalysed reaction is (Assume pre exponential factor is same $):$