- A$TiCl_3$
- B$FeCl_3$
- C$CoCl_2$
- ✓All of these
$Ti^{3+} = [Ar]\, 3d^1$ (one unpaired electron)
$Fe^{3+} = [Ar] \,3d^5$ (five unpaired electrons)
$Co^{2+} = [Ar]\, 3d^7$ (three unpaired electrons)
So all of them are coloured.
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$Ag | Ag^+(0.1\,M) || Ag^+(1\,M) | Ag$ at $298\,K$ is ............ $\mathrm{V}$
$A$. The stability of the hydrides decreases in the order $\mathrm{NH}_3>\mathrm{PH}_3>\mathrm{AsH}_3>\mathrm{SbH}_3>\mathrm{BiH}_3$
$B$. The reducing ability of the hydrides increases in the order $\mathrm{NH}_3<\mathrm{PH}_3<\mathrm{AsH}_3<\mathrm{SbH}_3<\mathrm{BiH}_3$
$C$. Among the hydrides, $\mathrm{NH}_3$ is strong reducing agent while $\mathrm{BiH}_3$ is mild reducing agent.
$D$. The basicity of the hydrides increases in the order $\mathrm{NH}_3<\mathrm{PH}_3<\mathrm{AsH}_3<\mathrm{SbH}_3<\mathrm{BiH}_3$Choose the most appropriate from the option given below:
Choose the correct answer from the options given below: