- AAmmonia
- BAniline
- CMethylamine
- DN - methyl aniline
Explanation:
Methyl amine is the strongest base.
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In the above first order reaction the initial concentration of $\mathrm{N}_{2} \mathrm{O}_{5}$ is $2.40 \times 10^{-2}\, \mathrm{~mol} \,\mathrm{~L}^{-1}$ at $318 \,K.$ The concentration of $\mathrm{N}_{2} \mathrm{O}_{5}$ after $1\, hour$ was $1.60 \times 10^{-2}\, \mathrm{~mol} \,\mathrm{~L}^{-1}$, The rate constant of the reaction at $318\, \mathrm{~K}$ is $.....\,\times 10^{-3} \mathrm{~min}^{-1}$. (Nearest integer)
[Given: $\log 3=0.477, \log 5=0.699$ ]
$\left[\right.$ Given $, E_{C u^{2+} / C u}^{o}=0.34\, V , E _{ NO _{3}^{-} / NO_2 }^{\circ}=0.96\, V$ (Rounded-off to the nearest integer) $E _{ NO _{3} / NO _{2}}^{\circ}=0.79 \,V$ and at $298 \,K$ $\left.\frac{ RT }{ F }(2.303)=0.059\right]$