MCQ
Which of the following compounds are optically active
- A$(I)$ and $(III)$
- B$(I)$ and $(II)$
- ✓$(II)$ and $(III)$
- D$(I), (II)$ and $(III)$
✓
Answer
Correct option: C.
$(II)$ and $(III)$
c
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The most stable canonical structure among the given structure is
Select the correct order
→$(a)$ $CO < C{O_2} < CO_3^{2 - }$ $ \Rightarrow $ Bond length
$(b)$ ${O_2} < {O_3} < O_2^{ - 2}$ $ \Rightarrow $ Bond length
$(c)$ ${N_2} < N_2^ + $ $ \Rightarrow $ Bond energy
Product is
The $C - H$ bond length is minimum in the bond formed by
→How many bonds (bond order) does $B_2$ have ?
→Manganese ions $(Mn^{2+})$ can be oxidised by Persulphate ions $S_2O_8^{2-}$ according to the following half-equations,
→$S_2O_8^{2-} + 2e^- \longrightarrow 2SO_4^{2-}$
$Mn^{2+} + 4H_2O \longrightarrow MnO_4 + 8H^+ + 5e^-$
How many moles of $S_2O_8^{2-}$ are required to oxidise $1\, mole$ of $Mn^{ 2+}$ ?
In the following reaction,
MnO2, + 4HCl → MnCl2 + 2H2O +Cl2
2 moles of MnO2 react with 4 moles of HCl to form 11.2L Cl2, at STP.
Thus, percent yield of Cl2 is:
MnO2, + 4HCl → MnCl2 + 2H2O +Cl2
2 moles of MnO2 react with 4 moles of HCl to form 11.2L Cl2, at STP.
Thus, percent yield of Cl2 is:
The half-cell reaction is the one that:
A given mass of gas expands from the state $A$ to the state $B$ by three paths $1, 2$ and $3$ as shown in the figure. If $w_1, w_2$ and $w_3$ respectively be the work done by the gas along three paths then
→If an electron is transferred from $B$ to $A$ , then reaction is possible when
→