- ✓$DC{H_2}C{H_2}C{H_2}Cl$
- B$C{H_3}C{H_2}CHDCl$
- C$C{H_3}CHDC{H_2}C{H_2}Cl$
- D$C{H_2}CHClC{H_2}D$
$C{H_3} - C{H_2} - \mathop {\mathop {\mathop {\mathop {{C^ * }}\limits_{|\,\,\,\,\,} }\limits_{Cl} }\limits^{|\,\,\,\,\,} }\limits^{H\,\,\,\,} - D$; $C{H_3} - \mathop {\mathop {{C^ * }}\limits_{|\,\,\,\,}^{|\,\,\,\,} }\limits_{D\,\,}^{H\,\,} - C{H_2} - C{H_2} - Cl$
$C{H_3} - \mathop {\mathop {{C^ * }}\limits_{|\,\,\,\,}^{|\,\,\,\,} }\limits_{Cl\,\,}^{H\,\,} - C{H_2}D$
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. . . . . (Given that the value of solubility product of $A B \left( K _{ sp }\right)=2 \times 10^{-10}$ and the value of ionization constant of $H B \left( K _{ a }\right)=1 \times 10^{-8}$ )
${A_2}(g)\, + \,{B_2}(g)\,\overset {{K_1}} \leftrightarrows \,2AB(g)\,\,\,......(1)$
$6AB\,(g)\,\,\overset {{K_2}} \leftrightarrows \,\,3{A_2}(g)\, + \,3{B_2}(g)......(2)$
The relation between $K_1$ and $K_2$ is

